When a rock thrown straight upwards gets to the exact top of its path, its velocity is:?

Question

a. zero and its acceleration is zero
b. about 10 m/s and its acceleration is zero
c. about 10 m/s and its acceleration is about 10 m/s/s
d. zero and its accerleration is about 10 m/s/s

Answer 1

The answer is d
Since it is at its top most part, it cannot move higher. So, velocity should be zero (this represents a turning point... the velocity vector starts to point downwards after having pointed upwards until this moment) (Thus options b and c are eliminated)

But acceleration due to gravity will ALWAYS remain constant at 9.8m/s/s or approx 10m/s/s.

Think of it this way to eliminate option a...
If acceleration was to be zero, then since no force acts on that object, it would stay up there for ever. But since this does not happen in reality, the correct answer is

d

Answer 2

The answer is d,
Since it has reached the top of the path it is no longer moving up and hasn't started moving down. If the acceleration was zero at that point it would float in the air at that point instead of coming back down.

Answer 3

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Answer 4

d. zero and its accerleration is about 10 m/s/s answer

Answer 5

the answer is d, it comes to a stop when it reverses direction, but its acceleration is constant

Answer 6

a

Answer 7

def. D

Answer 8

a.