1st year - $38750
6th year - $68750
During the period of 5 years he got a raise of $30000 i.e., $6000 per year.
If it continues to be the same, the raise in next 4 years would be $6000 multiplied by 4 = $24000.
So, the salary would be $92750 in the 10th year.
2007-05-23 19:41:43
·
answer #1
·
answered by Jain 4
·
0⤊
0⤋
1st yr is $38 750 and 6th yr is $68 750 means each year increment is $6 000.
at 10th year = $38750 + $6 000 x 9 = $ 92 750
2007-05-24 02:43:04
·
answer #2
·
answered by hsm 2
·
0⤊
0⤋
If you assume the raises are constant (graph of salaries is linear), then raise each year is (68,750 - 38,750)/6 = 30,000/6 = 5000 / yr, so in 10th year salary is 38,750 + 10(5000) = 88,750.
On the other hand, if you assume the % of increase is constant, then
68,750 = 38,750r^6
1.77419 = r^6
and salary in year 10 =
38,750r^10 = 38750(1.77419)^(10/6) =
100,756.23
2007-05-24 02:57:43
·
answer #3
·
answered by Philo 7
·
0⤊
0⤋
each year the raise is 6000 dolars. becasue 5 (5 years from the first year) divided by the amount of money made in 5 years is 6000. 68750 plus 6000 times 4, since from year 6 to year 10 is 4 years then the number is
68750 times 4(6000)
2007-05-24 02:42:49
·
answer #4
·
answered by student 2
·
0⤊
0⤋
The answer is $92,750.
$68,750 (current salary) - $38,750 (initial salary) = $30,000
divide $30,000 by 5 years = $6,000 is the raise he gets annually
$6,000 x 4 more years to reach his 10th year = $24,000
$68,750 (current salary) + $24,000 (raise for his next 4 years) = $92,750 is his salary on his 10th year on the job.
2007-05-24 02:41:56
·
answer #5
·
answered by chinita.eyes 1
·
0⤊
0⤋
68,750-38,750=30,000/5=6,000x9
=54,000+38,750=92,750 for the tenth year i hope this works
2007-05-24 02:41:52
·
answer #6
·
answered by drakelungx 3
·
0⤊
0⤋