How do you solve for tan2x=0?

Question

or tan 2x = 1?

Answer 1

tan(2x) = 0
2x = 0, ±π, ±2π, ±3π, ...
x = 0, ±π/2, ±π, ±3π/2, ...
or x = πn/2 for any integer n

and
tan(2x) = 1
2x = π/4, 5π/4, 9π/4, ...
(or -3π/4, -7π/4, ...)
x = π/8, 5π/8, 9π/8, ...
(or -3π/8, -7π/8, ...)
or x = (4n+1)π/8 for any integer n.

Answer 2

x=1/2

Answer 3

tan2x=0
2x=0
x=0
tanx=0
tan0=0
x=0

Answer 4

tan2x = 0
2x = 0, nπ
x = 0, nπ/2

tan 2x = 1
2x = π/4 + nπ
x = π/8 + nπ/2

Answer 5

tan 0, tan180, tan 360, tan 540 tan 720=0
2x=0, 180, 360, 540, 720
x=0, 90, 180, 270, 360 assuming that 0<
Since 1 is positive, the angle must be in the first and third sector or the ASTC region.
Therefore, antitan 1=45
2x=45, 225, 405, 585
x=22.5, 112.5, 202.5, 292.5 assuming that 0<

Answer 6

only one logic:

if tan A = 0, horizontal line.

possible answers are 0 or pi

but A = 2x

divide by 2, answers are 0 or pi/2.

same as for the next one.

if tan A = 1, diagonal line, therefore 45 degrees or pi/4.

divide by 2, answer is pi/8.

if the problem involves quadrants, add a coefficient to the previous answer.

Answer 7

Tan 2x 1

Answer 8

By your imagination x=0
2) 2x=pi/4
x=pi/8

Answer 9

Use a tirg identity. If you have sin(2x)/cos(2x)=tan(2x) that is how you get tan. So therefor sin(2x)/cos(2x)=0. Since it isn't good practice to divide something by zero then the only real answers are when sin(2x)=0. So 2x=sin^-1(0) and x=sin^-1(0)/2.

Answer 10

tan2x=0
2x=(tan^-1)0
2x=0
x=0 degree

tan2x=1
2x=(tan^-1)1
2x=45
x=22.5 degree