2007-05-23 18:50:35 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
√(m+3) - √(m-1) = 1
Put the square roots on opposite sides of the equation:
√(m+3) = √(m-1) + 1
Now square both sides:
m+3 = (m-1) + 2√(m-1) + 1
=> 2√(m-1) = 3
=> m - 1 = (3/2)^2
=> m = 13/4.
2007-05-23 18:55:37 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
â(m + 3) - â(m - 1) = 1
m + 3 - 2â(m + 3)(m - 1) + m - 1 = 1
2â(m + 3)(m - 1) = 2m + 1
4(m^2 + 2m - 3) = 4m^2 + 4m + 1
4m^2 + 8m - 12 = 4m^2 + 4m + 1
4m = 13
m = 13/4
2007-05-24 02:11:34 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
â(m+3)- â(m-1)=1
(â(m+3)- â(m-1))^2=1^2
(m+3)- 2â((2m+2) )+(m-1)= 1
-2â((2m+2) )= -2m-2
â((2m+2) )=m+1
ãâ((2m+2) )ã^2=ã(m+1)ã^2
2m+2= m^2+2m+1
m^2-1=0
(m+1)(m-1)
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2007-05-24 02:18:31 · answer #3 · answered by mikeal_engstrom 1 · 0⤊ 0⤋
How dare you get people to do your homework for you !
2007-05-24 01:58:58 · answer #4 · answered by Maria puggum dog lover 2 · 0⤊ 2⤋