Help me i need this today (y)+9)(2y-3)=0?

Question

#1 (y)+9)(2y-3)=0 #2 m^2 +2m-15=0 #3 8r^2=24r #3 b^2-49=0 # 4 c(3c+16)=0 #5 z^4+8z^3 - 9z^2=0 #6 9y -7)(2y^2+7y-15)=0 plese help

Answer 1

#1 (y+9)(2y-3)=0
2y^2 -3y + 18y -27 = 0
2y^2 + 15y -27 = 0
(2y-3)(y+9)=0
y = 3/2 and -9

#2 m^2 +2m-15=0
(m+5)(m-3)=0
m = -5 and 3

#3 8r^2=24r
8r^2 -24r = 0
8r(r-3)=0
r = 0 and 3

#3 b^2-49=0
b^2 = 49
b = sqrt 49
b = + or - 7

# 4 c(3c+16)=0
c = 0 and -16/3

#5 z^4+8z^3 - 9z^2=0
z^2(z^2 + 8z - 9)=0
z^2(z+9)(z-1)=0
z = 0 and -9 and 1

#6 (9y -7) (2y^2+7y-15)=0
(9y -7)(2y - 3)(y+5) = 0
y = 7/9 and 3/2 and -5

Answer 2

1)(y+9)(2y-3)=0
y+9=0 or 2y-3=0
y=-9 or 2y=3
y=3/2

2)m^2+2m-15=0
(m+5)(m-3)=0
m=-5 or m=3

3)b^2-49=0
b^2=49
b=+/-[49^(1/2)]
=7 or -7

4)c(3c+16)=0
c=0 or 3c+16=0
3c=-16
c=-16/3

5)z^4+8z^3-9z^2=0
(z^2)(z^2+8z-9)=0
(z^2)(z+9)(z-1)=0
z^2=0 or z+9=0 or z-1=0
z=0 or z=-9 or z=1

6)(9y-7)(2y^2+7y-15)=0
(9y-7)(2y-3)(y+5)=0
9y-7=0 or 2y-3=0 or y+5=0
y=7/9 y=3/2 y=-5

Answer 3

1. (y+9)(2y-3)=0 y=-9 or 3/2

2. m^2+2m-15=0
( m+5)(m-3)=0 m=-5 or 3

3.8r^2=24r
8r^2/8r=24r/8r r=3

4.b^2-49=0
(b-7)(b+7)=0 b=-7 or 7

5.c(3c+16)=0 c=0 or -5 1/3 (-16/3)

6.z^4+8z^3-9Z^2=0
z^2(z^2+8z-9)=0
z^2(z+9)(z-1)=0
z=0 -9 or 1

7.(9y-7)(2y^2+7y-15)=0 y=7/9,3/2, or -5
9y-7=0 9y=7 y=7/9
2y^2+7y-15=0
(2y-3)(y+5)=0 y=3/2 or -5

Answer 4

You asked it earlier also. See my reply there. But I would suggest you to learn the things rather than getting these solved for you by somebody else.