If a triangle has an area 92 cm and a side length of 16 cm, what is the length of the altitude to this side of the triangle
2007-05-23 17:41:28 · 6 answers · asked by bigjoe711 1 in Science & Mathematics ➔ Mathematics
Area = (1/2) * base * corresponding altitude.
92 = (1/2) * 16 * h
92 = 8h
h = 92/8
h = 11. 5 cm
The altitude drawn from the vertex opposite the side of 16 cm length is 11.5 cm.
2007-05-23 17:46:19 · answer #1 · answered by Akilesh - Internet Undertaker 7 · 0⤊ 0⤋
1/2 x base x height = area of triangle
1/2 x 16 x ht = 92
8 x ht = 92
height = 92/8
= 11.5 cm
By using phythogoras' theorem and let the length of the altitude be x cm,
x = sqrt(11.5^2 + 16^2)
= sqrt(388.25)
= 19.704 cm
2007-05-24 05:17:38 · answer #2 · answered by helping_people 2 · 0⤊ 0⤋
area = 1/2 Base * Altitude
92 = 1/2 (16) A
so
A = 11.5
2007-05-24 00:44:07 · answer #3 · answered by lovingdaddyof2 4 · 0⤊ 0⤋
A=1/2 BH(BA)
Altitude= 8 sqaure root of 3
(It's a 30-60-90)
2007-05-24 00:48:03 · answer #4 · answered by Monee 1 · 0⤊ 1⤋
theoretically if the triangle was an equilateral (all sides are the same), then the height would be 11.5
however, u side "a side" so we do not know the lenght of the other two sides. so, all of those that answered is wrong since the other 2 sides are NOT GIVEN TO YOU.
2007-05-24 00:48:54 · answer #5 · answered by musicxD 2 · 0⤊ 1⤋
11.5 cm
2007-05-24 00:45:27 · answer #6 · answered by sabbah 2 · 0⤊ 0⤋