one mole of any gas at stp has a volume of 22.4 liters. if a scuba diver's oxygen tank can hold 300 liters of oxygen how many moles of oxygen are in the tank?
2007-05-23 14:36:36 · 5 answers · asked by ahhhhhh 1 in Science & Mathematics ➔ Chemistry
use PV=nRT (or, as my friends and i call it, "pivnert")
for the first eqn,
PV=nRT
(P)(22.4) = (1)(.082)(273)
22.4 P = 22.386
P = .999 liters
(STP is defined as having a temp of 273 K)
(R = .082 when you are using liters)
now use that for the next eqn
PV = nRT
(.999)(300) = (n)(.082)(273)
299.81 = 22.386 n
n = 13.393
there 13.393 moles of O in the tank!
---you might want to check me on that...i don't know for sure if it is implied that the scuba tank is at STP...you might need to find molecular weight or something (which i would not be able to help you with)
___EDIT___
ok, i'm stupid...i got the right answer, but i did it the ridiculously long way
2007-05-23 14:49:12 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You seem to be missing information about the actual conditions of the tank. It is unlikely to be at 0 C and 1 atm.
Otherwise, adjust the 300 liters of the scuba tank to STP and then divide the adjusted volume by 22.4 to get the moles
2007-05-23 14:42:07 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋
300 / 22.4 = 13.4 moles
2007-05-23 14:40:46 · answer #3 · answered by Soichiro 2 · 0⤊ 0⤋
300/22.4 = 13.4 moles
2007-05-23 14:41:29 · answer #4 · answered by Anonymous · 0⤊ 0⤋
answer;300\22.4=13.3 litres of oxygen
2007-05-23 14:45:31 · answer #5 · answered by Dr. Eddie 6 · 0⤊ 0⤋