Help me!!! Math...?

Question

Can someone tell me how to solve them? Can you please put down the answer too? I've been trying to solve it for 1hr. now... LAWL I hate these equations

1) 10 to the power of 2n-4 = 10 to the power of n divided by 10 to the power of 6

2) 10 to the power of 2n-1 = 10 to the power of 5 divided by 10 to the power of n

ahh... thx :)

10^(2n-4) = 10^(n)/ 10^(6)

thx for all ur help everyone. It really helps. xD

for 1, I can also do something my teacher did...

2n/ n. If I do that to one side, I'll have to do n/n. then it will also be n-4=6.. I just forgot, so I had to ask

Answer 1

1) 10^(2n - 4) = (10^n)/(10^6)

10^(2n - 4) = 10^(n - 6)

2n - 4 = n - 6

n - 4 = -6

n = -2

2) 10^(2n - 1) = (10^5) / (10^n)

10^(2n - 1) = 10^(5 - n)

2n - 1 = 5 - n

3n - 1 = 5

3n = 6

n = 2

Answer 2

I agree with suesysgo for #2 but #1 is wrong.

10^(2n-4)=(10^n)/(10^6)
10^(2n-4)=10^(n-6)
2n - 4= n - 6
2n - 4 - n = n - 6 - n {subtract n}
n - 4 = -6 ( this leaves a negative)
n - 4 + 4 = - 6 + 4 {add 4}
n= -2

Hope this helps. They aren't that bad. It just takes time and patience.

Answer 3

Your equation is not clear.


10^(2n-4)=10^((n/10)^6) ??

10^(2n-1)=((10^5)/10)^n ??