Given the concentration of either hydrogen ion or hydroxide ion, use the ion product constant of water to calculate the concentration of the other ion at 298K.
H= 1.0 X 10-4M
OH= 1.3 X10-2M
If you can help me please explain how you did this, my book is very confusing.
2007-05-23 14:15:16 · 2 answers · asked by whitebuffalo 3 in Science & Mathematics ➔ Chemistry
water dissociates slightly into H+ and OH- . the reaction is
H2O <--> H+ + OH-
the equilibrium constant for this reaction (Kw) is 10^-14.
you know that:
Kw = [H+][OH-]
you can plug in the given values for Kw and [H+] to solve for [OH-] and then plug in the given values for Kw and [OH-] to solve for [H+]
hope this helps. let me know if you have any questions
2007-05-23 14:22:33 · answer #1 · answered by bballl 2 · 0⤊ 0⤋
The multiplication of the ionization of H+ and OH- in water is always 1 x 10E-14.
So take the numbers in yur problem and divide them into 1 x 10 E-14 and you have your answer.
For example, your first answer will be 1 x 10 E-10
2007-05-23 14:19:42 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋