chemistry help please easy calculation!?

Question

if a total of 13.5 moles of NaCHO3 and a 4.5 moles of C6H8O7 react how many moles of CO2 and Na3C6H5O7 will be produced

3NaHCO3 +C6H8O7-----> 3CO2 +3H2O +Na3C6H5O7

Answer 1

I didn't bother to check to see if the equation is balanced, but assuming it is:
3 moles of the first compound plus 1 mole of the second give you 3 moles each of the next 2 compounds and one mole of the last.
You have a ratio of 3 to 1 of the first 2 compounds (just like the equation), so you get 3 moles CO2, 3 moles, H20 and 1 mole of the last compound for every 3 moles of the first compound.

Thus the answer is 13.5 moles CO2 and 4.5 moles of the last compound.

Answer 2

This is a normal stoichiometry problem. Since moles of NaCHO3 is exactly 3 times as much as C6H8O7, there is no limiting reactant.

Just use the molar ratios to calculate the moles of the 2 products you list.