Ok, the first question was: using the laws of exponents, prove that any number raised to the power 0 is 1. I answered with- in dividing, subtract exponents if the bases are the same. 3^5/3^5=x exponents are the same so x^0=1.
I need help to finish the question.
1. What if we look at a number raised to the power of 3, then to the power of 2, then to the power of 1 and then to the power of 0? What is the pattern? Thanks so much!
2007-05-23 13:36:22 · 3 answers · asked by krisy 1 in Science & Mathematics ➔ Mathematics
3 to the third would be 27, simple enough
3 to the second would be 27/3 or 9 again simple enough
3 to the first would be 9/3 or 3, simple enough
as the pattern continues to 3^0 the product is again divided by 3 and 3/3 would be 1
that is why 3^0 would be 1
2007-05-23 13:42:39 · answer #1 · answered by andrewdladd 2 · 0⤊ 0⤋
2^3 = 8
2^2 = 4
2^1 = 2
as the exponent goes down 1 on the left, the value on the right is divided by 2, so if we do it 1 more time,
2^0 = 1
2007-05-23 20:43:08 · answer #2 · answered by Philo 7 · 0⤊ 0⤋
(((3^3)^2)^1)^0= 0.....when you raise an exponent to another power you multiply the numbers
2007-05-23 20:47:07 · answer #3 · answered by Anonymous · 0⤊ 1⤋