a grocer has two kinds of nuts, one that costs$5 per kilogram n another that costs $5.40 per kilogram. how ma?

Question

a grocer has two kinds of nuts, one that costs$5 per kilogram n another that costs $5.40 per kilogram. how many kilograms of each type of nut should be mixed in order to hav 40 kg of a mixture worth $5.25 per kg?

using just one variable

Answer 1

the 40kg mixture implies a combination of nuts costing 5.40/kg and 5.00/kg.
If X represents the amount of kgs contributed by the nuts costing 5.00/kg,
40-X represents the contribution by the nuts costing 5.40/kg

Therefore, 5(X) + 5.40(40-x) / 40 = 5.25 kg
solve for X

5x + 216 - 5.40x / 40 = 5.25
5x + 216 -5.40x = 210
-0.4x= -6
x= 15 kg @ $5.00/kg
25kg@$5.40/kg

Answer 2

Hi Dear Wish You a Very Happy New Year. Here is the solution to your problem: 1 Kilogram Apples Cost = £ 1.35 ....(Given) i.e. 1 Kg = £ 1.35 ......(i) So,to get the cost of 1.6Kg apples we multiply both sides of Equation (i) by 1.6 i.e. 1.6 * 1 Kg = £ (1.6 * 1.35) So, 1.6Kg = £ 2..16 Hence,1.6 Kilogram Apples cost £ 2.16.

Answer 3

reminds me of a joke... whats the difference between beer and deer nuts? beer nuts run about $3.50 for 1/4 pound while deer nuts are just under a buck.

Answer 4

weight: x + y = 40
value: 5.00x + 5.40y = 5.25(40)

multiply 1st equation by 5.00 and subtract from 2nd:

5.00x + 5.40y = 5.25(40)
5.00x + 5.00y = 5.00(40)
---------------------------------
............. 0.40y = 0.25(40)

y = 25, x = 15