you find an equation that satisfies the given condition...how do you do this? do you put it in slope intercept form?
2007-05-23 13:19:12 · 6 answers · asked by john d 2 in Science & Mathematics ➔ Mathematics
To be parallel the lines will have the same slope. The equation on a line is y=m*x +b where m = slope and b = y-intercept.
The slope of the line between (3,14) and (9,8) is -1. The change in Y = -6 and the change in X = 6. Slope = change in Y over change in X.
Since the second line goes through the origin (0,0) its y-intercept = 0. So the equation of a line with a slope of -1 and an intercept = 0 is:
Y = -X
2007-05-23 13:28:53 · answer #1 · answered by Chim000 2 · 1⤊ 0⤋
The line through those points would have slope equal to (14-8)/(3-9) = -1. Any line parallel to that will have the same slope. Since it passes through the origin, the y-intercept is zero. So your line is:
y = -x
2007-05-23 13:24:59 · answer #2 · answered by jcsuperstar714 4 · 1⤊ 0⤋
The slope can be calculated from the given two points,
m = (14-8)/(3-9) = -1
Therefore, the equation is
y = -x+b
But b=0 because the y-intercept is zero since it passes through the origin.
The final equation becomes,
y = -x
2007-05-23 13:26:12 · answer #3 · answered by sahsjing 7 · 1⤊ 0⤋
The slope of the known line is
m = (14-8)/(3-9) = 6/-6 = -1.
Since the y-intercept is at (0,0)...
y = -x
2007-05-23 13:24:34 · answer #4 · answered by TychaBrahe 7 · 1⤊ 0⤋
Find the slope(m) of the equation using (y2-y1)/(x2-x1).
Substitute for m in y=mx+c
Find the intercept(c) by substituting for x and y in the above equation and solving for c.
That will give you the equation x+y=17
The line that will be parallel is x+y=0
2007-05-23 13:29:04 · answer #5 · answered by d_shyamala 1 · 1⤊ 0⤋
m=(y2-y1)/(x2-x1)
m=(8-14)/(9-3)=-6/6=-2
since it is parallel, the line has the same slope = -2
since it is through the origin, the y int is 0
so y=2x
2007-05-23 13:24:32 · answer #6 · answered by leo 6 · 0⤊ 1⤋