2007-05-23 12:52:44 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
4x^2y -68xy -72y =
4y(x^2 - 17x - 18) =
4y(x-18)(x+1)
2007-05-23 12:58:42 · answer #1 · answered by Steve A 7 · 1⤊ 0⤋
take out the GCF (greatest common factor) which in this case is 4y...
4y(x^2 - 17x - 18)
now, factor the bracketed expression
4y(x+1)(x-18)
2007-05-23 19:56:07 · answer #2 · answered by anonymous 2 · 1⤊ 0⤋
4x²y -68xy -72y
Divide thru by 4y
4y(x² -17x -18)
4y(x + 1)(x - 18)
2007-05-23 19:57:28 · answer #3 · answered by Robert L 7 · 1⤊ 0⤋
: 4x^2y -68xy -72y=y(4x^2-68x-72)
=y(4x^2+4x-72x-72)
=y(4x(x+1)-72(x+1).
4y*(x+1)(x-18)answer
2007-05-23 20:04:16 · answer #4 · answered by Anonymous · 1⤊ 0⤋
4x^2y-68xy-72y
=4y(x^2-17x-18)
=4y(x^2+x-18x-18)
=4y{x(x+1)-18(x+1)
=4y(x+1)(x-18)
2007-05-23 20:23:35 · answer #5 · answered by alpha 7 · 0⤊ 0⤋
4y(x-18)(x+1)
2007-05-23 19:58:03 · answer #6 · answered by TychaBrahe 7 · 1⤊ 0⤋
4y(x^2-17x-18)
4y(x-18)(x+1)
2007-05-23 20:00:14 · answer #7 · answered by Dave aka Spider Monkey 7 · 1⤊ 0⤋