solve for time ? A =P (1+ r/n)^nt?

Answer 1

One way...

Divide by P
A/P = (1 + r/n)^nt

Take the natural log of both sides.
ln(A/P) = ln[(1 + r/n)^nt ]

Bring nt to the front of the ln expression.
ln(A/P) = nt ln(1+r/n)

Divide by n ln(1 + r/n)
[ln(A/P)] / [n ln(1 + r/n)] = t

Answer 2

A =P (1+ r/n)^nt
A/P = (1+ r/n)^nt
log [base(1+ r/n)] (A/P) = nt
{log [base(1+ r/n)] (A/P) } /n = t

Answer 3

A/P = (1 + r/n)^(nt)
log (A/P) = (nt).log (1 + r/n)
t = (1/n).[ (log A/P) / log (1 + r/n ]

Answer 4

I am not sure if you want to rewrite the equation in terms of t or not but here it is.

t = ln(A/P)/[n*ln(1+r/n)]

You should be able to plug and chug with this. ln = natural log.