Can anyone help me set up the equation?

Question

The sum of three consecutive even integers is at least 43. What are the smallest even integers that satisfy this condition?

Answer 1

I'm not available to help set it up, but I might be able to lend a hand in taking it down... let me know...

Answer 2

You don't know the first even number, so call it x.
The next even number is x + 2.
the next even after that is x + 4.
"The sum of" means add them up.

(x) + (x + 2) + (x + 4) > 43. Combining like terms,
3x + 6 > 43. Adding -6,
3x > 37. Dividing by 3,
x > 37/3, or x > 12 1/3. Since you're looking for the smallest even integers that work, pick the first even number after 12 1/3 for x. It's 14. The other evens, then, are 16 and 18.

Answer 3

x+y+z > 43

Answer 4

n + (n+2) + (n+4) > 43 ......... <<<==== set up here
3n + 6 > 43
3n > 37
n > 12.333
n = 14

14 + 16 + 18 = 48 ....

seems to work
try lower
12 + 14 + 16 = 42 ..

must be good

Answer 5

choose first integer as 2n (it is even whatever n is)
second 2n+2
third 2n+4
all are consecutive even integers
sum is 6n+6 which is also even so it must be equal to 44+x in order to be the smallest
6n+6=44+x
6n=38+x
smallest x satisfies is 4
6n=42
2n=14 answer!
the others are 16 and 18

Answer 6

14+16+18

for the equation: x + (x+2) + (x+4) >=43, so 3x+6 >=43, or 3x>=37, or x >= 37/3

Answer 7

Let 2x be the 1st number
then 2x+2 = 2nd number
and 2x+4 = 3rd number
So 6x+6 = 43
6x = 37
So 42 is 1st number that works
6x = 42 --> x=7
2x=14 = 1st number
16 = 2nd number
18 = 3rd number

Answer 8

14, 16, 18

Answer 9

x+x+1+x+2= 43
3x+3=43
-3 -3
3x=40
--- ---
3 3
x = 13,14 and 15.. but that is only 42.. did you write the problem right?

Answer 10

wrong problem
because the sum of an even numbers is even number