Two trains are running on parallel lines in the same direction at speed of 40kmph and 20kmph respectively. The

Question

Two trains are running on parallel lines in the same direction at speed of 40kmph and 20kmph respectively. The faster train crosses a man in the second train in 36 seconds.The length of the faster train is"

give calculation process"

Answer 1

Suppose we fix the slower train as the coordinate system, (ie. we view the slower train as not moving), then the faster train will be moving 20 kmph with respect to the slower train.

Since the faster train takes 20 seconds to pass the the man on the slower train, this means the length of the faster train is:

20 km/h * 36 sec * 1 hr/ 3600 sec = 0.2 km = 200m

Answer 2

I believe the answer is one fifth (1/5) km

The faster train is traveling twice as fast as the other train. So, in theory, if the slower train was to stop th faster train would pass the man in half the time it originally did.

36 divided by 2 is 18 seconds

convert 18 seconds into hours
60s=1m 60m=1h

18s/1 * m/60s * h/60m = h/200

then multiply the speed of the train by the time
40km/h * h/200 = km/5

I believe I am doing this right, I havent done this kind of math in a few years. I hope it helps.

Answer 3

relative speed of the trains=40-20=20km/h
time taken to cross the man=36 seconds=1/100 hour

so,length of the train=distance travelled by it in 1/100 hour at the speed of 20km/h
=1/100*20 km
=1/5 km
=200 m

so, the length of the faster train is 200 metres.

Answer 4

We know the faster train is going 20 kmph faster

so

Distance (D) = rate x time

D = 20 * 36/3600

There are 3600 seconds per hour

D = 0.2 km or 200 meters is the length of the train.
.

Answer 5

relative speed 1/2=40-20=20kmph
it takes 36 secs to cross a man so length=20kmph*36secs=20kmph*.01hrs=.2km=200mts
check calculations urself

Answer 6

length/time=speed
l/36s=(40-20) kmph [Relative Velocity/Speed Concept]
l/36=20*1000/(60*60)
l/36=200/36
l=200m

Answer 7

both trains r moving in same direction,now, resultant velocity is 40-20=20 kmph, we need to convert it into m/s,now,
20 kmph= 20 . 5/8 = 25/2 m/s.
time taken = 36 secs
now, distance covered = 36 . 25/2 = 450 mts.

Answer 8

imagine one train is stationary.
the other one then moves at effectively 20kmh as the man would be moving at 20kmh towards the front of the faster train
so it ends up 20kmh slower
20kmh/60mins
=1/3km a minute
36seconds /60=3/5
3/5*1/3=
1/5km
or 0.2km or 200m

Answer 9

The difference in speed is 20km/h
= 20000m/3600s

time taken=36s.

Since distance travelled=speed x time:
distance=20000m*36s/3600s
= 20000m/100
=200m.

Answer 10

what should this suppose to be? riddle?