A certain compound contains two atoms of element x for every three atoms of sulphur (atomic mass 32.06).I f 10

Question

A certain compound contains two atoms of element x for every three atoms of sulphur (atomic mass 32.06).I f 10g of the compound contains 1.87g of sulphur , the atomic mass of x is

"give calculation process"

Answer 1

So, the formula of the compound is X2S3
Figure out moles of sulfur:
1.87 g sulfur / 32.06 g/mol = 0.0583 mol sulfur

From formula of cmpd, calculate moles of X in the 10 g of the compound:
0.0583 mole S(2 mol X/3 mol S) = 0.0389 mols of X

Calculate mass of X in 10 g compound:
10.0 g cmpound - 1.87 g sulfur =8.23 g X

Calculate molar mass of X
8.23 g X / 0.0389 mol X = 212 g/mol

Answer 2

Protons... the elements on the periodic table are organized by number of protons. How many electrons they have is influenced by the number of protons. In most cases, the number of electrons and number of protons is the same, but because in most cases this also means that the valence shell is not complete, atoms seek other atoms to bond with. The noble gases have complete valence levels, so they don't seek out things to bond with.

Answer 3

Follow the ball
Start with mass
Convert to moles 1.87/32.1 = A
By the empirical formula, moles of other atom=2A/3
Convert to grams 8.17/(2A/3) = atomic mass wt

Answer 4

first, divide 1.87 g S by its molar mass, 32.1 to get 0.05826 moles of S. Divide this by 3, then multiply by 2 to get the moles of x. This equals 0.03884 moles of x. If 0.03884 moles of x weigh 8.13g (10g total - 1.87 g S), then the molar mass of x equals 209.3 g (g / mol), which also equals your answer,

209.3 amu