the answer is option(a)CH3Cl.....
shudnt it be CCl4...? it has more Cl, so more bond polarity, so more dipole moment?
plz give the answer in clear words (dont confuse me).........
2007-05-23 05:47:42 · 4 answers · asked by practico 1 in Science & Mathematics ➔ Chemistry
All the above compounds are tetrahedral in shape. Since the dipole moment of a bond is aligned parallel to that bond, we have a tetrahedron of dipoles.
If all the dipoles are equal, they will cancel out if arranged tetrahedrally, that happens in CCl4, it has a 0 dipole moment.
2007-05-23 05:59:38 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 1⤋
the answer, as seen above, is certainly not CCl4 for the reasons stated above. The answer must be based on electronegativities. The greater the differences of electronegativity, the higher the dipole moment. The electronegativity of H is about 2.2 or so, Cl is about 3.2 or so. This means that a), CH3Cl must be the answer, because there is a much higher electronegativity unbalance.
2007-05-23 06:42:52 · answer #2 · answered by Verdad 2 · 0⤊ 0⤋
Are you sure the answer is a) , I would have gone for c)
but you have to check on that one , I'm not certain.
One thing is for sure however, it's definitely not CCl4 because there is no dipole, the 4 Cl surround the lone carbon atom and the negative charges of the Cl are dispersed around the carbon. ok?
2007-05-23 06:04:47 · answer #3 · answered by George D 2 · 1⤊ 0⤋
CHCl3 could have the terrific dipole 2nd. The atoms are in a tetrahedron with the Carbon in the middle. The negativity of the Clorine is what creates the dipole and 3 of them create a larger internet stress.
2016-11-26 19:54:55 · answer #4 · answered by ? 4 · 0⤊ 0⤋