tRINOMIAL INTERMIDIATE ALGEBRA
2007-05-23 04:47:52 · 6 answers · asked by Ben A 1 in Science & Mathematics ➔ Mathematics
Well...you can't really answer that without something on the left-hand side of the equation. We can't solve for X until we know what X^2+X+1 equals to.
Maybe you're not explaining the question clearly enough...
2007-05-23 04:54:18 · answer #1 · answered by Pinsir003 3 · 0⤊ 0⤋
Solve it with the quadratic formula if the equation is equal to zero.
X² + X + 1 = 0
x = (-b +- â(b² - 4ac))/2a
x = (-1 +- â(1² - 4))/2
x = (-1 +- â(-3))/2
x = (-1 +- iâ(3))/2
.
2007-05-23 04:54:42 · answer #2 · answered by Robert L 7 · 0⤊ 0⤋
This is impossible to solve. You have multiple variables and not enough given information. However, you can still graph the function. I would imagine that you either missed some given information or you were just supposed to graph it. Hope this helps
2007-05-23 05:39:05 · answer #3 · answered by wolverine205 3 · 0⤊ 0⤋
X^2+X+1=?
x^2+x+1 does not have real factors.
x^2+x+1-? = 0
x = [-1 +/- sqrt(1-4(1-?))]/2
x = -.5 +/- .5sqrt(-3-4?)
2007-05-23 05:00:18 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
using ax^2 + bx + c = 0,
x = -1(+/-)sqrt(-3)/2
x = (-1+3i)/2
or
x = (-1-3i)/2
where i is the complex number of sqrt -1
2007-05-23 05:00:07 · answer #5 · answered by correct? 1 · 0⤊ 0⤋
You need to use the Quadratic formula.
2007-05-23 04:51:30 · answer #6 · answered by jjsocrates 4 · 0⤊ 0⤋