Jason plans to fence a rectangular area with 140 meters of fencing. He has written the formula A = w(70 - w) t

Answer 1

What's the question???

Answer 2

Ok, I'm going to presume you want to find the optimal width and length so that he gets the most area fenced in.

First, even without doing any work. The largest area would be obtained by making a circular fence. But he wants a rectangular area, so the largest area would be surrounded by a square.

Now let's do the math.
A = w(70 - w)
= 70w - w²

The max or min is achieved when the first derivative is 0, or when 70-2w = 0, or wen w=35.

So you have, as guessed, a square 35m on a side, and with an area of 1225.. A circle, by the way would have gotten you about 1560.

Answer 3

Assume w = width
Then (140 - 2w)/2 =length = 70-w
So area = length X width = w(70-w)
A= w(70-w) = 70w -w^2
Assuming he want area to be max,
dA/dw = 70 -2w
So w max = 35 and l max = 35
The rectangle is a square with A = 35^2 = 1,225 ft^2.

BTW, what does the "t" stand for?

Answer 4

Not sure of question

you do know that perimeter = 140

perimeter is also 2(L+W)

thus 140 = 2(L+W)

70 = L+W
L = 70-W

Area is also L*W

so it is also W(70-W) I have no idea where the t comes from