PLEASE HELP!! thnx
2007-05-23 03:55:35 · 7 answers · asked by kb 1 in Science & Mathematics ➔ Physics
Assuming that the air density, object profile and AoA is the same, the drag quadruples. This is because drag is a function of Velocity ².
Let drag D = (const) * V² where the constant is 0.5*density*area*Coefficient of Drag and V is the velocity.
Doubling V
D= (const) * (2*V)²
or D= (const) * 4V² which 4 times the earlier drag.
2007-05-23 07:01:09 · answer #1 · answered by ? 6 · 1⤊ 0⤋
The drag is proportional to the velocity squared so if you double the velocity, the drag goes up by a factor of 4
2007-05-23 11:00:31 · answer #2 · answered by kdesky3 2 · 0⤊ 0⤋
All other variables being equal, it depends on the shape of the object.
A ball for example, because of the air pressure envelope in front of it and the vortex behind it, would incrementally increase drag much greater than a pointed object such as an arrowhead.
2007-05-23 11:03:21 · answer #3 · answered by Perplexed 5 · 0⤊ 0⤋
It depends on the object. For very small objects moving slowly through a fluid (e.g. drops of oil from an atomizer), the drag is proportional to speed. For lager objects moving quickly (e.g. a cannonball or a car), the drag is proportional to the square of the speed.
2007-05-23 11:53:12 · answer #4 · answered by dragonlord182 2 · 0⤊ 0⤋
The drag goes as the square of the velocity
2007-05-23 10:58:33 · answer #5 · answered by Gene 7 · 0⤊ 0⤋
the drag also become double.
but aerodynamic can change this value..
it all depends on how easily the air around the object travels..
2007-05-23 11:03:47 · answer #6 · answered by kish 2 · 0⤊ 0⤋
If the object is moving in a vacuum, there is no drag.
.
2007-05-23 12:33:00 · answer #7 · answered by Anonymous · 0⤊ 0⤋