What is the mass( in grams) of iron that contain the same number of atoms as 780g of potassium.
2007-05-23 03:22:34 · 5 answers · asked by Raphael A 3 in Science & Mathematics ➔ Chemistry
mass per mole of potassium=39g
780/39=20moles
mass of 1 mole of iron =56
56x20=1120g
2007-05-23 03:28:00 · answer #1 · answered by Anonymous · 0⤊ 1⤋
First, convert your g of K to particles using molar mass then Avogadro's number.
780 g K (1 mole K / 39 g K ) (6.022 x 10^23 particles K / 1 mole K) = 1.2 x 10^25 particles K
Now use this as # particles of Iron and convert back to grams.
1.2x10^25 particles Fe (1 mole Fe / 6.022 x 10^23 ) (55.9 g Fe / 1 mole Fe ) = 928.3 g of Fe
2007-05-23 10:32:48 · answer #2 · answered by embem171 4 · 0⤊ 1⤋
780 g K/39.1 g K/mol K = 19.95 mol K
19.95 mol Fe (55.85 g Fe/mol Fe) = 1.1 X 10^3 grams Fe
2007-05-23 10:29:49 · answer #3 · answered by hcbiochem 7 · 1⤊ 0⤋
60...
2007-05-23 10:29:57 · answer #4 · answered by Mark P. 5 · 0⤊ 2⤋
HERE
2007-05-23 10:28:36 · answer #5 · answered by xprof 3 · 0⤊ 2⤋