What is the equation of teh line that passes through (-6, 2) and has a slop of -2/3?

Answer 1

slope is -2/3 so

y = -2/3 x + c
or 3y+2x = C we can take another constant

as it passes through (-6,2) we get
3*2+2(-6) = C
or C = -6

so equation is 2x+3y = - 6

Answer 2

The equation you use is y = mx + b where
m is the slope of the line and b is the y-intercept ( where your line crosses the y-axis, the vertical line in the graph, the x-axis is the horizontal line). You put in the point you have (x,y) which is (-6,2) so
x = -6 and y = 2 with a slope m= -2/3 and solve for b. So now you have 2 = (-2/3)x + b. Solving for b you get b= -6. So now you go back to putting in x and y in your equation with the m you were given and the b you solved for and it is now true for any point on the line.
So the answer is y= (-2/3)x + (-6) or
y= (-2/3)x - 6 since adding a negative is the same as subtracting. You're good to go.

Answer 3

the answer is

y=-2/3x-2

you put (-6,2) in the equation y=mx+b as (x,y) and the m is always the slope.

so its (2)=-2/3(-6)=b

here u have to find b( the y intercept), so you times -2/3 by -6
-the answer is 4

so you have (2)= 4+b
- 4 -4
and then you get
-2=b

so you just put in the slope(m) and the y intercept(b) into y=mx+b and thats the equation of the line

y=-2/3x-2

Answer 4

y - 2 = (-2/3).(x + 6)
y = (-2/3).x - 2
or
3y = - 2x - 6
2x + 3y + 6 = 0

Answer 5

y=-2/3x-2
again m =-2/3
subs it in to get
2=4+c
-2=c
subs that in to get
y=-2/3x-2

Answer 6

y=-2/3x-2