English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

A charge is placed on a spherical conductor of radius r1. This sphere is then connected to a distant sphere of radius r2 (not equal to r1) by a conducting wire. After the charges on the sphere are in equilibrium:

a. the electric fields at the surfaces of the two spheres are equal

b. the amount of charge on each sphere is q/2

c. both spheres are at the same potential

d. the potentials are in the ratio v2/v1=q2/q1

e. the potentials are in the raion v2/v1=r2/r1

if anyone could give me any hints or try and explain how to get the answer that would be great :D

2007-05-22 23:24:30 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

c. The reason is that no electric field exist within a conductor at equilibrium. Since charges are free to move, if there's an electric field in the conductor then the charges will situate themselves in such a way that it goes to zero. At this point, since there is no electric field in the conductor, the potential difference between any parts of the conductor is 0, thus they are at the same potential.

2007-05-22 23:56:01 · answer #1 · answered by supastremph 6 · 0 0

both spheres are at the same potential

2007-05-23 07:01:21 · answer #2 · answered by Anonymous · 0 0

fedest.com, questions and answers