Radical Help?

Question

I need answers to these problems, it would be greatly apreciated. Thanks in advance


1. 6√5-2√5+8√5
2. √15+8√15-12√15
3. 4√3+2√12
4. 8√54-4√6
5. 8√32-4√8
6. 2√45+4√20

7.√5x=10
8. √4x=6
9. 3√5=√-n
10. √p-9=0
11. √3a+2=0
12. 6-√2y=-2

Answer 1

1. since the square root has the same number, the solution is
(6-2+8)√5 = 12√5
2. do the same way as above ^^
3. the square root has different numbers then we should simplify it first and make them into same numbers. the solution is:
4√3+2√12
=4√3+(2.√(4*3))
= 4√3+(2*2√3)
=4√3+4√3=8√3
4. do the same way as no 3 ^^
5 and 6. idem

7. √5x=10
square both sides, you will get
(√5x)²=10²
5x=100
x=100/5
x=20

8. do the same way as no 7

9. 3√5=√-n
square both sides, you will get:
(3√5)²=(√-n)²
45=-n
n=-45

10. √p - 9 =0
√p=9
(√p)²=9²
p=81

11 and 12. try them by your own.....you can do it ^^

hope it helps you ^^

Answer 2

1. 12 sqrt 5
2. -3sqrt 15
3.4 sqrt3+2sqrt12= 4 sqrt3+4sqrt3= 8 sqrt3
4. 20sqrt 6
5. 24sqrt2
6. 17sqrt5
7.sqrt5x=10=sqrt5x^2=10^2= 5x=100= x=20
8.sqrt4x=6 = sqrt4x^2=6^2=4x=36 x=9
9. 3sqrt5=-sqrtn= 3sqrt5^2=-sqrtn^2=9*5=n= 45=n
10. sqrt p-9=0 sqrt of p-9^2=0^2= p-81=0 p=81
11.sqrt of 3a+2=0=sqrt of3a+2^2=0^2= 3a+2=0
3a=-2 a=-2/3
12. 6-sqrt2y=-2=6-6-sqrt2y=-2-6= -sqrt2y=-8 -sqrt2y^2=-8^2=
2y=64 y=32

Answer 3

how did u put that square root sign?