solubility question.......help?

0 ⤊

solubility question.......help?

Calculate the solubility of Ca(OH)2 in a 0.700M NaOH solution at 43°C, given that the Ksp of Ca(OH)2 is 7.50 x 10-6 at that temperature

answer in micro Molar units.

thx heaps

2007-05-22 22:29:24 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

[Ca2+] = 7.5x10^-6/(4x0.49) = 3.83 micromoles

2007-05-23 05:52:25 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋

SInce NaOH is a strong base, [NaOH]=[OH]
To find solubility of Ca(OH)2,

Ksp=[Ca2+]{OH-]
7.50x10^-6 = [Ca][.700M]
[Ca] = 7.50x10^-6 / .700M
[Ca] = 1.07x10^-5 M
1.07x10^-5 M * 1000000micromolars / 1 M = 107.14 micromolars

2007-05-23 12:54:26 · answer #2 · answered by kpgkn29 2 · 0⤊ 0⤋