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A voltaic cell is constructed with one electrode compartment consists of a silver strip placed in a solution of AgNO3, and the other has a nickel strip placed in a solution of NiCl2. The overall cell reaction is given below.
2 Ag+(aq) + Ni(s) => 2 Ag(s) + Ni2+(aq)

(a) Select the correct half-reactions that occur in the two electrode compartments.
2 Ag+(aq) + e- => 2 Ag(s)
2 Ag(s) => 2 Ag+(aq) + 2 e-
Ni(s) + 2 e- => 2 Ni(aq)
Ag+(aq) + e- => Ag(s)
Ag(s) => Ag+(aq) + e-
2 Ni(s) => Ni2+(aq) + 2 e-
Ni(s) => Ni2+(aq) + 2 e-
Ni2+(aq) => Ni(s) + 2 e-

(b) Which electrode is the anode, and which is the cathode in the following equation? (Type your answer using the format C for carbon.)
2 Ag+(aq) + Ni(s) => 2 Ag(s) + Ni2+(aq)

anode ____________

cathode ____________

2007-05-22 20:19:40 · 3 answers · asked by sydney 1 in Science & Mathematics Chemistry

3 answers

Ag+(aq) + e- => Ag(s)
Ni(s) => Ni2+(aq) + 2 e-

recall the reaction at the anode is ALWAYS OXIDATION, and is ALWAYS NEGATIVE for a voltaic, galvanic cell .. cathode is always REDUCTION, and positive ... so cathode Ag+(aq) + e- => Ag(s) reaction at the anode Ni(s) => Ni2+(aq) + 2 e- the electrode at the anode is Ni(s) at the cathode is Ag(s)

i always remember Anode---> Oxidation because both of them start with A VOWEL

2007-05-26 20:19:59 · answer #1 · answered by Anonymous · 0 0

Ag+(aq) + e- => Ag(s)

2 Ni(s) => Ni2+(aq) + 2 e-

Ag is the cathode and Ni is the anode.

2007-05-23 05:52:41 · answer #2 · answered by ag_iitkgp 7 · 0 0

If the scale factor of Figure X to Figure Y is 1.75, this usually means that the distances between points in Figure X are 1.75 times longer than the distance between the corresponding points in Figure Y, which would mean that X is an enlargement of Y. This is the same as stating that Figure Y is a reduction of Figure X, so the answer is B.

2016-05-20 10:56:02 · answer #3 · answered by bernetta 2 · 0 0

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