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it's a trade offer in a keeper league. consider my team has D. Lee and D. Wright already, so either way, i'll have one of their teammates.

2007-05-22 20:11:42 · 6 answers · asked by Jephatitis E 6 in Sports Fantasy Sports

6 answers

Beltran and Soriano are both five tool players of about equal value. go with the player you would have more fun watching all season long and have some fun.

2007-05-23 01:21:44 · answer #1 · answered by Frizzer 7 · 0 0

It depends on if your league has OBP counted as a stat. Soriano gets on base alot, he has gotten on in every game hes played but one. His run production is better also, as a result of him being on base so much. His SB total at the end of the year will most likely be greater than beltran's.

Beltran hits for power better than Soriano. He has more HR's and RBI's than Soriano does so far this year, and it will probably be the case by year's end as well. Beltran also has a better avg than Soriano, .304 to soriano's .284.

Soriano is a little younger than Beltran is, and will probably play for longer in the league, if this is a factor for your decision.

I would say that Beltran is the better pickup. He is better in most categories than Soriano is.

But like the other guy said, either guy will help out your team alot

2007-05-23 04:09:35 · answer #2 · answered by jimboxyz1 4 · 0 0

Who cares if you have their teammates?
How does that have anything to do with it?
What are they going to hold each others hands and pray for good fantasy numbers?

Beltran, here is in a better offensive line up, and will put better numbers in the years to come.

2007-05-23 08:39:11 · answer #3 · answered by Mike E 2 · 0 0

I think Beltran will end up being the Better player of the two but, either way you will end up with a very fine ball player.

2007-05-23 03:24:54 · answer #4 · answered by a1c_big_tex 3 · 0 0

Beltran because hes on my team too

2007-05-23 04:25:13 · answer #5 · answered by Sole 3 · 0 0

Beltran, better player in a better offense

2007-05-23 09:32:17 · answer #6 · answered by Papdopalous 2 · 0 0

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