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If 4.25g of a diatomic gas is stored in 2.0L container at a temperature of 22degree C and a pressure of 10.8psi, what is the identity of the gas?

2007-05-22 17:08:40 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

MM= gRT/PV = 4.25 g * 0.08206 * 295 K / (0.735 atm * 2 L)
MM= 70.0 g/mol

Most likely chlorine (Cl2 MM is 71 g/mole).

2007-05-22 17:13:49 · answer #1 · answered by TheOnlyBeldin 7 · 0 0

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