5w(w^2-7w+3) +2w(2+19w-2w^2)
2007-05-22 15:59:13 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5w^3 - 35w^2 + 15w + 4w + 38w^2 - 4w^3
w^3 + 3w^2 + 19w
w(w^2 + 3w + 19)
2007-05-22 16:03:25 · answer #1 · answered by McFate 7 · 0⤊ 0⤋
5w(w^2-7w+3) +2w(2+19w-2w^2)
5w^3 - 35w^2 + 15w + 4 w + 38 w^2 - 4 w^3
w^3 + 3w^2 + 19 <== this is the answer
2007-05-22 23:09:21 · answer #2 · answered by logivan_net 3 · 0⤊ 0⤋
Alright.
5w(w^2-7w+3) +2w(2+19w-2w^2)
Step 1: Distribute!!
5w^3-35w^2+15w + 4w + 38w^2 - 4w^3
Step 2: Combine Like Terms!!
w^3 + 3w^2 + 19w
the end [[:
2007-05-22 23:04:56 · answer #3 · answered by Anonymous · 0⤊ 0⤋
5w(w^2-7w+3) +2w(2+19w-2w^2) =
5w^3 - 35w^2 + 15w + 4w + 38w^2 - 4w^3 =
w^3 + 3w^2 + 19w = w(w^2+3w+19)
you can factor the last bit using irrationals but its not worth it!
2007-05-22 23:05:17 · answer #4 · answered by tsunamijon 4 · 0⤊ 0⤋
Distribute
5w^3 - 35w^2 + 15w + 4w + 38w^2 - 4w^3
Collect like terms
w^3 + 3w^2 + 19w
2007-05-22 23:03:13 · answer #5 · answered by piggy30 3 · 1⤊ 0⤋
5w(w^2-7w+3) +2w(2+19w-2w^2)
5w^3-35w^2+15w+4w+38w^2-4w^3
w^3+3w^2+19w
2007-05-22 23:03:47 · answer #6 · answered by Anonymous · 0⤊ 0⤋
3w^3-3w^2+19w
2007-05-22 23:04:40 · answer #7 · answered by savage708 3 · 0⤊ 0⤋
wow these numbers look like christmas tree decoration
2007-05-22 23:01:43 · answer #8 · answered by Anonymous · 0⤊ 0⤋