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sin x + cos x= (cos x / 1-tan x) + (sin x / 1-cot x)

2007-05-22 14:54:51 · 2 answers · asked by P 1 in Science & Mathematics Mathematics

2 answers

Jus do it this way
Multiply the right side by (1-tanx)(1-Cotx).
Then u get Sinx+CosX= Cosx(1-Cotx)+Sinx(1-tanx)/(1-tanx)(1-Cotx).
Now cross multiply
take d denominator on the right side and send it over 2 d left side and u get d same equation on both sides.
Ur equation is verified as d left now equals d right.

2007-05-22 15:07:46 · answer #1 · answered by ade o 1 · 0 0

RHS
= cos x / (1 - sin x / cos x) + sin x(1 - cos x / sin x)
= cos² x / (cos x - sin x) + sin² x(sin x - cos x)
= cos² x / (cos x - sin x) - sin² x/(cos x - sin x)
= (cos² x - sin² x) / (cos x - sin x)
= (cos x - sin x).(cos x + sin x) / (cos x - sin x)
= (cos x + sin x)
= LHS

2007-05-22 19:43:59 · answer #2 · answered by Como 7 · 0 0

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