These three lines:
(a) The line of sight from the top of the shorter building to the top of the tall one;
(b) A line straight across from the top of the shorter building which strikes the taller building at the same height as the top of the shorter building; and
(c) The additional height of the tall building above the short one
... form a right triangle. The hypotenuse is the line of sight (a), the legs are (b) and (c).
tan(angle) = opposite/adjacent
tan(angle_of_elevation) = (c) / (b)
tan(angle_of_elevation) = additional_height / distance_between_buildings
Plug in the values you know:
tan(37 degrees) = h / 28m
tan(37 degrees) * 28m = h
21.1m = h
That value, "h," is the height of the tall building above the shorter one, not the full height of the tall one. You have to add the height of the shorter building in, to get the tall building's height above the ground:
21.1m + 35m = 56.1m
2007-05-22 12:28:57
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answer #1
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answered by McFate 7
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Draw a diagram. You have a right triangle formed from the top of the short building, the 35m mark on the taller building, and the top of the taller building. Call the difference between the building heights h. Notice that tan(37) = h/35. So express this in terms of h and add it to 35 to find the full height of the taller building.
2007-05-22 12:33:00
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answer #2
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answered by Anonymous
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It would help if you draw the picture.
Let's call the height of the tall building x.
You have a right triangle between the buildings. One leg is 28 (the distance between the buildings). The other leg is (x - 35) because that's the distance between the top of the short building to the top of the tall building.
The angle adjacent to the 28m leg is 37 degrees.
So, you have
tan (angle) = opposite / adjacent
tan 37 = (x - 35) / 28
x - 35 = 28(tan 37)
x = 35 + 28(tan 37)
x = 35 + 21.0995
x = 56.0995 or approx 56.1 m
2007-05-22 12:32:18
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answer #3
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answered by Mathematica 7
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draw a picture. sounds like similar triangles or trigonometric ratios
always helps to have a smart study buddy.
cosine ratio maybe..lol umm
If these people got wrong answer...then I think they mis interpreted the angle from top of shorter to top of second, they didnt put angle of 37 degress and instead put that for the 'ground' angle between buildings.
2007-05-22 12:34:17
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answer #4
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answered by Anonymous
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Just look for the cotangent of 37 degrees, it is 1.3270, the adjacent side is 28m, th distance between buildings, cotangent is adjacent/opposite, the opposite side is 21.10 meters plus 35 m of the small building = 56.10 meters
2007-05-22 12:39:06
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answer #5
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answered by mimi 3
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i'm in algebra too and this 365 days we've not evaluation no longer something approximately math till Friday .. final 365 days i became in universal math yet i'm hoping this 365 days i bear in mind the flaws through fact we've not evaluation this textile for a 365 days..i'm so worry and that i've got not got notes nor an 8th grade attempt e book
2016-10-31 03:24:37
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answer #6
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answered by ? 4
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tan 37 = (side opp) / 28
side opp = 21.1 m
Now add that to the height of the shorter bldg.
Height of tall building = 21.1 + 35 = 56.1 m
.
2007-05-22 12:32:37
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answer #7
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answered by Robert L 7
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Mexico.
2007-05-22 12:33:36
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answer #8
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answered by Anonymous
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