the question is... two buildings are 28m appart. the angle of elevation from the top of the shorter building to the top of the taller one is 37 degrees. the shorter building is 35 m tall. what is the hight of the taller building?
2007-05-22 12:12:22 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
difference in height = x
theta = 37 degrees
tan(37)=x/28
x=28tan(37)
=28*0.7536
=21.1m
The taller building is 35m + 21.1m = 56.1m tall
2007-05-22 12:26:06 · answer #1 · answered by gudspeling 7 · 0⤊ 0⤋
Use the tangent function. Let x = 28 m be the distance between the buildings, and y = the difference in height of the two buildings. The tangent of the angle of elevation is:
tan 37° = y/x. which implies x tan 37° = y.
tan 37° ~ 0.75. So y ~ (28 m.)(0.75) ~ 21 m.
To find the height of the taller building, we simply add 21 m. to the height of the shorter building:
height of the taller building ~ 21 m. + 35 m. ~ 56 m.
2007-05-22 19:30:24 · answer #2 · answered by MathBioMajor 7 · 0⤊ 1⤋
Let's do the math of it. 35m is the shorter building which is 37º on top of it to the taller building. first thing you can do is to figure it out as a triangle on top of the smaller building. by using tangent you can calculate the opposite and the adjacent of the triangle.
calculations:
tan Φ = opposite/adjacent
tan 37º = x/28m
x = (tan 37º) (28m)
x = (0.75355405)(28)
x = 21.09m is the additional height of the taller building or the unknown value opposite from the 37º of the shorter one.
then you use this value of x to find the height of the taller building.
height of the taller building = x + (35 m tall of the shorter one).
height = 21.09 + 35m
height = 56.09m. is the tall of the taller building.
2007-05-22 20:01:05 · answer #3 · answered by edison c d 4 · 0⤊ 0⤋
Draw a right triangle with the hyp. running from the top of one building to the top of the other. The base of the triangle runs between the two buildings parallel to the ground. Using the definition of tan for right triangles tan(theta)=opp/adj
tan(37)=x/28 x=21.099m
x is the difference between the heights of the two buildings
So the height of the second building is about 35+21.099 or 56.1m
2007-05-22 19:27:25 · answer #4 · answered by Cristal R 1 · 0⤊ 1⤋
its 35 + 28 * tan 37
2007-05-22 19:27:50 · answer #5 · answered by eric s 2 · 0⤊ 0⤋
56.0995 meters
difference in height is 28 tan(37)
add that to 35
2007-05-22 19:32:44 · answer #6 · answered by wilmer 5 · 0⤊ 0⤋
35 + 28tan(37)
2007-05-22 19:25:53 · answer #7 · answered by factor_of_2 3 · 1⤊ 0⤋
ok im only in the 8th grade so im not 100% sure about my answer but i tried my hardest:
the height of the second building is 57m
good luck
hope i helped
2007-05-22 19:35:05 · answer #8 · answered by BrOokLyN 4 · 1⤊ 0⤋
what ever you do dont jump, they r both 2 high.
2007-05-22 19:27:49 · answer #9 · answered by Anonymous · 1⤊ 1⤋