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Specific gravity of a 33% (NH4)SO4 solution is 1.1 what mass of (NH4)SO4 would be required to prepare 201mL?

CHEM HELP!!! =]

2007-05-22 11:51:40 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

1 answers

201 ml of the soln weighs = 1.1x201 = 221.1 g

Mass of (NH4)2SO4 = .33 x 221.1 = 72.963 g

2007-05-23 05:53:16 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋

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