You were given an scalene triangle... 17 as it's base(hypotenuse), and 15 and 8 are the sides... I'm looking for it's area, but I don't know how to get the height of the triangle... how do you find it's height?
2007-05-22 11:34:07 · 6 answers · asked by Juan C 6 in Science & Mathematics ➔ Mathematics
yeah... i'm sorry... i mean right triangle... jejeje... sorry guys...
2007-05-22 11:39:42 · update #1
The height of a triangle is perpendicular to its base. On the right triangle, either leg is the base and the other is the height.
A = ½(b)(h) = ½(8)(15) = 60.
2007-05-22 11:41:42 · answer #1 · answered by Anonymous · 1⤊ 0⤋
This is a right triangle, because a^2 + b^2 = c^2. So the base is really 8 and the height is 15.
2007-05-22 18:37:38 · answer #2 · answered by TychaBrahe 7 · 0⤊ 0⤋
the height of a triangle is 15
2007-05-22 18:36:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Well it looks like you already have the height (15) because a is the shortest side, b is the medium sized side, in this case, 15, and c is the longest side. And the area would be base x height / 2, which would be (15x8)/2=60
2007-05-22 18:44:37 · answer #4 · answered by Anonymous · 1⤊ 0⤋
First thing you have to do is to find the Area of the Triangle.
Area = ½absin Φ
= ½(15)(17) sin 30º
= 63.75 sq. units
We know the formula of the area, then we use this equation for finding the height, we have:
A = ½bh
substitute the sq. unit of the area in the equation and the base,
A = ½bh
63.75 = ½(17)h
63.75 = 8.5h
h = 7.5 units. is the right answer! perpendicular to the
(hypotenuse) base.
2007-05-22 19:15:33 · answer #5 · answered by edison c d 4 · 0⤊ 0⤋
bisect the triangle, which is 15, if you use A^2+B^2=C^2
sqroot C^2
2007-05-22 18:37:49 · answer #6 · answered by Anonymous · 0⤊ 0⤋