I need lots of help pLEASe?
WHat are the lengths of two legs of an
30-60-90 traiangle if the length of an hypotuse is 12sqroot 3?
2007-05-22 11:24:31 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i'll seek the help of an @merican m@th passer for you. will send the answer soon.
2007-05-22 11:28:59 · answer #1 · answered by Anonymous · 1⤊ 0⤋
actually, the legs are 6 sqrt 3 and 18. The first answerer is wrong... he jumped the gun there all because he saw sqrt 3 somewhere without questioning where it was. Wrong leg, joe. LOL. Its cool though. He was right about the legs being 1, 2, sqrt3 in relation
Are you doing Trigonometry or generic Geometry/Algebra. Trig functions might mean jack to you, so that third answerer might not be too useful either. Those relationships I mentioned can be verified with Trig, but unless you know trig dont bother trying to decipher that answer.
2007-05-22 11:35:59 · answer #2 · answered by Anonymous · 0⤊ 0⤋
The leg opposite 30deg angle is:
12sqrt(3)sin(30)
= 12sqrt(3) / 2
= 6sqrt(3).
The other is 12sqrt(3)cos(30)
= 12sqrt(3)sqrt(3) / 2
= 18.
No need to feel outc@st.
2007-05-22 11:37:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the legs are 1/2 the hypotenuse and 1/sqrt 3
so, 6 and 12
2007-05-22 11:27:55 · answer #4 · answered by Mike 2 · 1⤊ 2⤋
Special Right Triangles.....
http://www.themathpage.com/aTrig/30-60-90-triangle.htm
you have to work backwards
2007-05-22 11:35:06 · answer #5 · answered by Anonymous · 0⤊ 1⤋
sin(30) = .5
opp/hyp = x/12(sqrt(3)) = .5
x = 6(sqrt(3))
cos(30) = sqrt(3)/2
adj/hyp = y/12(sqrt(3)) = sqrt(3)/2
2y = 12(sqrt(3))(sqrt(3)) = 36
y = 18
Check this
18^2 + 6(sqrt(3))^2 =
324 + 108 = 432 = (12(sqrt(3)))^2
2007-05-22 11:34:19 · answer #6 · answered by TychaBrahe 7 · 0⤊ 0⤋