2007-05-22 08:35:37 · 9 answers · asked by JaLisa M 1 in Education & Reference ➔ Homework Help
2+8+14+20+26+32+38+44+50+56+
62+68+74+80=574
2007-05-22 08:45:27 · answer #1 · answered by Anonymous · 0⤊ 0⤋
574
I filled in the numbers in the series...start with 2 and add 6 to each number until you reach 80, so numbers in series would be 2, 8, 14, 20, 26, 32, 38, 44, 50, 56, 62, 68, 74, 80. The sum is 574.
2007-05-22 15:45:04 · answer #2 · answered by margecutter 7 · 0⤊ 0⤋
x = 2 the first number in a regular series
y = 80 the last number in the series
z = 14 the total numbers in the series
answer = (2 + 80) / 2 * (14)
41 * 14 = 574
2007-05-22 15:45:14 · answer #3 · answered by Menehune 7 · 0⤊ 0⤋
a=2
d=6
to find the total number of terms..
80= a + (n-1)d
80= 2 + (n-1)6
80=2 + 6n - 6
80=6n - 4
84=6n
n=84/6=14
Now sum of the AP= n/2(2a + (n-1)d
=14/2{2(2) + (14-1)6}
=7{4+78}
=7{82}
=574
2007-05-22 15:41:15 · answer #4 · answered by Anu_K 2 · 1⤊ 0⤋
574
2007-05-22 17:21:31 · answer #5 · answered by random bailey 5 · 0⤊ 0⤋
Given your pattern, 574
2007-05-22 15:45:39 · answer #6 · answered by Griggles04 2 · 0⤊ 0⤋
574.
2007-05-22 16:07:12 · answer #7 · answered by lasereye360 2 · 0⤊ 0⤋
hmmmm
2007-05-22 15:46:18 · answer #8 · answered by AW 3 · 0⤊ 0⤋
i dont see how anyone can answer that...That's not really a question
2007-05-22 15:39:13 · answer #9 · answered by steamhead10 2 · 0⤊ 0⤋