English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

1) 0.0m/s2 , (2)1.0m/s2, or 4.9m/s2, or 9.8m/s2 and the accleration of gravity is 9.8m/s2.

2007-05-22 07:42:51 · 4 answers · asked by margoretewhitfield 1 in Science & Mathematics Physics

4 answers

9.8m/s^2 or 9.8ms^-2
because you would fall straight down with gravity unless there was fristion against the surface in which case you would need to specify how much friction but i would assume that there is none

2007-05-22 07:53:27 · answer #1 · answered by Anonymous · 1 0

You would accelerate towards the ground at 9.8 m/s^2 until terminal velocity is reached, at which point you will stop accelerating and your velocity will remain relatively constant.

2007-05-22 15:12:50 · answer #2 · answered by Brian K² 6 · 0 0

9.8m/s^2 on a verticle surface it is in free fall.

2007-05-22 15:11:36 · answer #3 · answered by Anonymous · 0 0

It depends on the angle of the surface. But there's no way it can be greater than 9.8 m/s²

Doug

2007-05-22 14:48:52 · answer #4 · answered by doug_donaghue 7 · 0 0

fedest.com, questions and answers