(3 points )If A B and B C, what can you conclude? Why? What if A B and B C? If A B and B C?
Because subsets are transitive (meaning that all the members of B are also in C and all the members of A are also in B, therefore all the members of A are also in C).
If AB and B C, then A C, because subsets are transitive.
If A B and B C, then A C, because subsets are transitive.
(4 points) Write down all possible subsets of {a, b, c, d}
{a,b,c,d}, {a,b,c}, {a,b,d}, {b,c,d}, {a,c,d}, {a,b}, {a,c}, {a,d}, {b,c}, {b,d}, {c,d}, {a}, {b}, {c}, {d}, { }.
16 sets
(2 points) Without writing them down what are the number of subsets of the set A = {a, b, c, d, e, f}? Of set B = {a, b, c, d, e, f, g, h, i, j}?
number of subsets of the set A={a,b,c,d,e}? of set B = {a,b,c,d,e,f,g,h}?
number = 2^(nelts)
subsets of A = 2^5 = 32
subsets of B = 2^8 = 256
Need help:
Express the following in set-builder notation: M = {1, 2, 3, 4}
2007-05-22
07:11:37
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