math question dealing with % and averages?

Question

Ok, here's my situation. I'm taking a pass/fail course and would like to know what I need on my final exam tomorrow in order to pass the class. So far I recieved a 55 on test 1, which accounts for 21% of the overall grade, a 62 on test 2, which accounts for 24% of the overall grade, and an 82 on a term paper, which accounts for 25% of the overall grade. The final equal 30%. What do I need to get on the final exam in order to average a 60 for the course? If someone math major could walk me through this it would be highly appreciated. thanks.

Answer 1

We just need to total the percentages multiplied by their weights.

Test 1: 55% and weight is 21%. So, we have 21 X .55 = 11.55

Test 2: 62% and weight is 24%. So, we have 24 X .62 = 14.88

Test 3 (Term paper): 82% and weight is 25%. So, we have 25 X .82 = 20.5

Adding these three, 11.55 + 14.88 + 20.5 we get 46.93 or almost 47. So, you need just 13 (or if your teacher is very fussy, 13.07 against that balance 30% weight) which works out 13.07/30 = 43.57 or let us say 44%

So you can relax and thus score much better.

Answer 2

Okay. Add 41+55+62+82 together . You get 240. 41 is half of 82. Divide 240 by 3.5 You get 60.8 .
You need to make at least a 60 on your final.
When you figure you final tally by writing down your final grade and write down half of your final grade as well. Divide by 4.5.

Answer 3

You need to score 43.567 to get an average of 60.

55 x 0.21 + 62 X 0.24 + 82 x 0.25
= 46.93

this is what you have scored till now

hence you need to add 60 - 46.93 = 13.07 to reach 60

since this exam accounts for 30%, you will need to score 13.07/0.3 = 43.567.

Answer 4

You don't need a math major. A smart 4th grader could help you.

You have a weighted average

(55)(.21) + (62)(.24) + 82(.25) + n(.3) which must equal 60


11.55 + 14.88 + 20.5 + .3n = 60

46.93 + .3n = 60
.3n = 13.07

n = 43.56

Answer 5

that sound about right