A boat travels upstream at 3 mi/h. The same boat travels downstream at 8 mi/h. What is the rate in still water and the rate of the current?
2007-05-22 04:36:47 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Divide the difference by 2, which is 2.5 mph and the rate of the current The rate of the boat traveling at still water is then 5.5 mph. Going upstream 5.5 - 2.5 = 3 mph. Going downstream 5.5 + 2.5 = 8 mph. Q.E.D.
XR
2007-05-22 04:49:39 · answer #1 · answered by XReader 5 · 0⤊ 0⤋
You need the equation:
x-y = 3 where x is the speed of the boat and y is the speed of the water. THen you also need
x+y = 8
So x = 11/2 and thus y = 5/2
So the boat is going 5.5 mi/h and
the current is 2.5 mi/h.
QED
2007-05-22 04:49:24 · answer #2 · answered by Leetron 2 · 0⤊ 0⤋
If you paid attention during the lessons you'd know it's all about the difference between the two, yes?
What's the difference between 12 and 10?
2007-05-22 04:47:44 · answer #3 · answered by pik996 2 · 1⤊ 0⤋