2007-05-22 04:03:02 · 11 answers · asked by llaattiinnlloovvee3 1 in Science & Mathematics ➔ Mathematics
I'd suggest using the quadratic formula. If the equation is expressed as ax^2 + bx + c = 0, then x = (-b +/- sqrt(b^2 - 4ac)) / 2a. Here, a = 3, b = -8, and c = 3. So x = (8 +/- sqrt(8^2 - 4*3*3)) / (2*3) = (8 +/- sqrt(64 - 36)) / 6 = (8 +/- sqrt(28)) / 6 = (8 +/- 2*sqrt(7)) / 6 = (4 +/- sqrt(7)) / 3 = 4/3 + (1/3)sqrt(7) or 4/3 - (1/3)sqrt(7).
2007-05-22 04:06:36 · answer #1 · answered by DavidK93 7 · 1⤊ 0⤋
a million. D 2. D 3. D 4. B 5. D 6. B 7. B 8. D 9. D 10. D eleven. D 12. C 13. A 14. C 15. B sixteen. A 17. a million=B, 2=A, 3=D, 4=C 18. B 19. a million=B, 2=A, 3=D, 4=C 20. C 21. A 22. D 23. C 24. C 25. B
2016-11-26 00:58:13 · answer #2 · answered by ? 3 · 0⤊ 0⤋
There is a formula in Vedic Mathematics which lets us solve a quadratic equation....
Therefore if ax^2+bx+c=0 is the quadratic equation then the formula for the roots of the equation are
x1=((-b)+(sqrt(b^2-4*a*c)))/(2*a)
x2=((-b)-(sqrt(b^2-4*a*c)))/(2*a)
where x1,x2 are the 2 roots of the equation......
In your case b=8,a=3,c=3...So substitute and find the roots...
2007-05-22 04:20:14 · answer #3 · answered by jadoo 2 · 0⤊ 0⤋
by completing the square:
3x^2 - 8x = -3
x^2 - 8/3x = -1
divide the term with x by two then square the result.
x^2 - 8/3x + 16/9 = -1 + 16/9
(x - 4/3)^2 = 7/9
x - 4/3 = + or - (sqrt 7)/3
therefore: x = (4 + sqrt 7) / 3 and x = (4 - sqrt 7 ) / 3.
they are irrational.
2007-05-28 17:22:59 · answer #4 · answered by megavinx 4 · 0⤊ 0⤋
Use the quadratic formula. In an equation Ax^2 + Bx + C = 0, we can take x = [-B +/- sqrt(B^2 - 4AC)]/(2A).
So x = 8 +/- sqrt(64-36) / 6. So simplifying gives:
4 +/- sqrt(7)
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3
2007-05-22 04:07:51 · answer #5 · answered by MikeyJ 2 · 0⤊ 0⤋
3(x^2 - 8/3x + 1) = 0
x^2 - 8/3x + (8/6)^2 - (8/6)^2 + 1 = 0
(x - 8/6)^2 - (64 - 36)/36 = 0
(x - 8/6)^2 - 28/36 = 0
(x - 8/6 - sqrt28/6)(x - 8/6 + sqrt28/6) = 0
x = 8/6 + sqrt28/6
x = 8/6 - sqrt28/6
2007-05-22 04:09:17 · answer #6 · answered by Anonymous · 0⤊ 0⤋
ax^2 + bx + c = 0
3x^2 - 8x + 3 = 0
the quadratic formula is ( -b +or- sq rt of b^2 - 4ac) divided by 2a
so,
8+or- sq rt (-8)^2-4(3)(3)
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2(3)
8+or- sq rt 28
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6
2007-05-22 04:09:12 · answer #7 · answered by banana boat 2 · 0⤊ 0⤋
There is no whole number as an answer in this.
By using a calculator, x=2.215 or x=0.45
2007-05-22 04:09:04 · answer #8 · answered by Anonymous · 0⤊ 0⤋
use the quadratic formula
2007-05-22 04:06:27 · answer #9 · answered by Anonymous · 0⤊ 0⤋
3x*x=3x^2
3x*-3=-9x
1*x=1x
-3*1=-3
(3x+1)(x-3)
2007-05-22 04:09:52 · answer #10 · answered by Ben 2 · 0⤊ 0⤋