Help PLease With Math! Please!?

Question

1. 4n^2 + 12n + 5 = 0
A. {-3/2, -1/2}
B. {-+3/2}
C. {-5/2, -3/2}
D. {-5/2, -1/2}

2. (2y^2/3) - y - 3 = 0
A. {-+ 3/2}
B. {-+ 3}
C. {-3/2, 3}
D. {-3, 3/2}

Answer 1

4n² + 12n + 5 = 0

4n + 2n + 10n + 5 = 0

2n(2n + 1) + 5 (2n + 1) = 0

(2n + 5)(2n + 1)

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Roots

2n + 5 = 0

2n + 5 - 5 = 0 - 5

2n = - 5

2n / 2 = - 5 / 2

n = - 5/2

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Roots

2n + 1 = 0

2n + 1 - 1 = 0 - 1

2n = - 1

2n / 2 = - 1/2

n = - 1/2

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The answer is D (- 5/2, - 1/2)

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Answer 2

1. 4n^2 + 12n + 5
factorized first -> (2n +5)(2n+1)=0
n= -5/2 or n= -1/2.
answers D

2. 2y^2/3 - y - 3 = 0
times with 3 first -> 2y^2 - 3y - 9 = 0
factorized - > (2y+3)(y-3)=0
y= -3/2 or y = 3
answers C