Factoring Fractions!? (1/121)x^2-4/49?

0 ⤊

2007-05-22 03:58:09 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Remeber that a^2x^2 - b^2 factors as (ax - b)(ax + b)
So
((1/11)x - 2/7)((1/11)x + 2/7)

2007-05-22 04:02:18 · answer #1 · answered by TychaBrahe 7 · 0⤊ 0⤋

(1/121) x^2 = (x/11)^2 and 4/46 = (2/7)^2
formula a^2-b^2 = (a-b)(a+b)

(x/11 -2/7) (x/11+2/7)

2007-05-22 04:03:26 · answer #2 · answered by maussy 7 · 0⤊ 0⤋

(x/11-2/7)(x/11+2/7)

2007-05-22 04:01:02 · answer #3 · answered by TfC_137 3 · 0⤊ 0⤋

((1/11)x+2/7)((1/11)x-2/7)

Is this what you're looking for?

2007-05-22 04:03:09 · answer #4 · answered by Jason K 2 · 0⤊ 0⤋

(x/11)^2-(2/7)^2
=(x/11+2/7)*(x/11-2/7)

2007-05-22 04:02:03 · answer #5 · answered by Anonymous · 0⤊ 0⤋