(1/36)x^2 - (9/25)
Factor
((1/6)x - (3/5))((1/6)x + (3/5))
.
2007-05-22 03:58:57
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answer #1
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answered by Robert L 7
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Since this is not an equation, you cannot exactly solve it. I will give a solution for (1/36)x^2 - (9/25) = 0.
Add (9/25) to both sides:
(1/36)x^2 = 9/25
Multiply both sides by 36:
x^2 = 324/25
Square root both sides:
x = 18/5
Recall that when taking the square root, the negative answer also works, so:
x = -18/5
Therefore, x = 18/5, -18/5.
2007-05-22 10:58:26
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answer #2
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answered by MikeyJ 2
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(1/36) x^2 = (x/6)^2 and (9/25) =(3/5)^2
formula a^2-b^2 = (a-b) (a+b)
your expression becomes (x/6-3/5) (x/6+3/5)
Isuppose you search the roots (x/6-3/5) =0
x/6=3/5 x= 18/5= 3.6
you find easily that the second root is -3.6
2007-05-22 11:00:40
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answer #3
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answered by maussy 7
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(1/36) x^2 = 9/25
Then multiply each side by the reciprical of (1/36) which is 36.
x^2 = 9/25(36)
x^2 = 12.96
Then take the square root of each side.
x = 3.6
2007-05-22 11:00:19
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answer #4
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answered by gwiz 1
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(1/36)x^2 = 9/25
x^2 = (9/25) * 36
x^2 = 324/25
x = +/- 18/5 = +/- 3-3/5
2007-05-22 11:00:07
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answer #5
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answered by TychaBrahe 7
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Take square root on both sides,
Its an identity :
a^2 - b^2 = (a + b)(a - b)
So u get: (x/6 + 3/5)(x/6 - 3/5)
2007-05-22 10:57:30
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answer #6
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answered by the_warper 2
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is there any more details included?
1/36= 6^-2
and thats all i know
2007-05-22 10:57:21
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answer #7
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answered by kim 2
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