Factor these. Math! Algebra 2B You'll get 10 points?

Question

4m to second power - 1 = ( ) ( )
a to second power + 2a + 1 = ( ) ( )
4x to second power + 12x + 9 = ( ) ( )
x to second power - 22x + 121 = ( ) ( )
9x to second power - 4 = ( ) ( )
9x to second power - 30x + 25 = ( ) ( )
4x to second power - 20x + 25 = ( ) ( )
x to second power - 24x + 144 = ( ) ( )
3n to second power - 3 = ( ) ( )
9h to second power + 60h + 100 = ( ) ( )
81a to second power - 400 = ( ) ( )
3a to second power - 48 = ( ) ( )
b to second power + 4b + 4 = ( ) ( )
25x to second power - 64 = ( ) ( )
12w to second power - 27 = ( ) ( )
g to third power - 25g = ( ) ( )
x to second power + 6x + 9 = ( ) ( )
36s to second power - 225 = ( ) ( )
4b to second power + 44b + 121 = ( ) ( )
x to second power - 16x + 64 = ( ) ( )
x to second power - 2x + 1 = ( ) ( )
d to second power - 49 = ( ) ( )

Answer 1

1.4m^2-1=(2m)^2-(1)^2=(2m+1)(2m-1)
2.a^2+2a+1
=(a)^2+2*a*1+(1)^2
=(a+1)^2
3.4x^2+12x+9
=(2x)^2+2*2x*3+(3)^2
=(2x+3)^2
4.x^2-22x+121
=(x)^2-2*x*11+(11)^2
=(x-11)^2
5.9x^2-4
(3x)^2-(2)^2
=(3x+2)(3x-2)
6.4x^2-20x+25
=(2x)^2-2*2x*5+(5)^2
=(2x-5)^2
7.x^2-24x+144
=(x)^2-2*x*12+(12)^2
=(x-12)^2
8.3n^2-3
=3(n^2-1)
=3{(n)^2-(1)^2}
=3(n+1)(n-1)
9)9h^2+60h+100
=(3h)^2+2*3h*10+(10)^2
=(3h+10)^2
10.81a^2-400
=(9a)^2-(20)^2
=(9a+20)(9a-20)
11) 3a^-48
=3(a^2-16)
=3{(a)^2-(4)^2}
=3(a+4)(a-4)
12)b^2+4b+4
=(b)^2+2*b*2+(2)^2
=(b+2)^2
13)25x^2-64
=(5x)^2-(8)^2
=(5x+8)(5x-8)
14.12w^2-27
=3(4w^2-9)
=3{(2w)^2-(3)^2}
=3(2w+3)(2w-3)
15.g^3-25g
=g(g^2-25)
=g{(g)^2-(5)^2}
=g(g+5)(g-5)
16.x^2+6x+9
=(x)^2+2*x*3+(3)^2
=(x+3)^2
17.36s^2-225
=(6s)^2-(15)^2
=(6s+15)(6s-15)
18.4b^2+44b+121
=(2b)^2+2*2b*11+(11)^2
=(2b+11)^2
19.x^2-16x+64
=(x)^2-2*x*8+(8)^2
=(x-8)^2
20)x^2-2x+1
=(x)^2-2*x*1+(1)^2
=(x-1)^2
21) d^2-49
=(d)^2-(7)^2
=(d+7)(d-7)

Answer 2

All this equations are solved employing the quadratic formulation. ax^2 + bx + c = 0 while x = [-b + - squareRt (b^2 - 4ac)]/2a b^2 + 3b - 4 = 0 b = [-3 + - squareRt (9 + sixteen)]/2 = (-3 + - 5)/2 b = a million b = -4 w^2 - 8w = 0 = w(w - 8) = 0 w = 0 w = 8 x^2 - 3x - 10 = 0 x = [3 + - squareRt (9 + 40)]/2 = (3 + - 7)/2 x = 5 x = -2 2x^2 - 7x + 5 = 0 x = [7 + - squareRt (40 9 - 40)]/4 = (7 + - 3)/4 x = 2.5 x = a million 4x^2 - 25 = 0 x = [+ - squareRt (4 hundred)]/8 = + - 20/4 x = 5 x = -5 z^2 - 5z = - 6 z^2 - 5z + 6 = 0 z = [5 + - squareRt (25 - 24)]/2 = (5 + - a million)/2 z = 3 z = 2 3a^2 + 4a = 2a^2 - 2a - 9 a^2 + 6a + 9 = 0 a = [- 6 + - squareRt (36 - 36)]/2 = (- 6 + - 0)/2 a = - 3 6y^2 + 12y +13 = 2y^2 + 4 4y^2 + 12y + 9 = 0 y = [- 12 + - squareRt (one hundred forty four - one hundred forty four)]/8 = (- 12 + - 0)/8 y = - 6/4 = - a million.5 3t^2 + 8t = t^2 - 3t - 12 2t^2 + 11t + 12 = 0 t = [- 11 + - squareRt (121 - ninety six)]/4 = (- 11 + - 5)/4 t = - 4 t = - 3/2 = - a million.5 3x^2 = 9x + 30 3x^2 - 9x - 30 = 0 x = [9 + - squareRt (80 one + 360)]/6 = (9 + - 21)/6 x = 5 x = -2 2x^2 + 5x^2 = 3x 7x^2 - 3x = 0 x(7x - 3) = 0 x = 0 x = 3/7 12x^2 + 8x = - 4x^2 + 8x 16x^2 = 0 x = 0 x^3 - 5x^2 + 4x = 0 x(x^2 - 5x + 4) = 0 x = 0 x^2 - 5x + 4 = 0 x = [5 + - squareRt (25 - sixteen)]/2 = (5 + - 3)/2 x = 4 x = a million x^3 + 3x^2 - 70x = 0 x(x^2 + 3x - 70) = 0 x = 0 x^2 + 3x - 70 = 0 x = [-3 + - squareRt (9 + 280)]/2 = (-3 + - 17)/2 x = - 10 x = 7 2x^3 = -2x^2 + 40x 2x^3 + 2x^2 - 40x = 0 x(2x^2 + 2x - 40) = 0 x = 0 2x^2 + 2x - 40 = 0 x = [-2 + - squareRt (4 + 320)]/2 = (-2 + - 18)/4 x = -5 x = 4

Answer 3

4m^2-1 = (2m)^2-1 = (2m-1)*(2m+1)

a^2+2a+a = a^2 +a+a+a= a(a+1) + (a+1)= (a+1)*(a+1)=(a+1)^2

4x^2 +12x +9 = (2x)^2 + 3*2 x +3*2x + 3*3 = 2x* ( 2x +3) + 3(2x+3) = (2x+3)(2x+3) = (2x+3)^2

x^2 -22x +121 = x^2 + 11x +11x +11^2 = x(x+11) + 11(x+11) = (x+11)*(x+11) = (x+11)^2

9x^2 -4 = (3x)^2 -2^2 = (3x+2)*(3x-2)

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learn this 3 :

1. (a+b)^2 = a^2 +2*a*b + b^2
2. (a-b)^2 = a^2 -2*a*b +b^2
3. (a+b) (a-b) = a^2 - b^2

this is always true for real numbers...
you just have to figure out "a" and "b"

Answer 4

And you get someone to do your homework?

Maybe - but it won't be me.