If an aqueous solution of sodium hydroxide has a [OH - ] = 1.0 10-3 at 298 K, what is the [H+]?

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2007-05-22 02:42:47 · 2 answers · asked by tim_childress 1 in Science & Mathematics ➔ Chemistry

In any aqueous solution at 298 K,
[H+] X [OH-] = 1.0 X 10^-14.

So, [H+] = 1X10^-14/1X10^-3= 1X10^-11

The pH of that solution is 11.

2007-05-22 02:47:34 · answer #1 · answered by hcbiochem 7 · 0⤊ 0⤋

[OH-] x [H30+] = 1.0 x 10-14
just plug in the value of OH-

2007-05-22 09:48:36 · answer #2 · answered by pacsky01 2 · 0⤊ 0⤋