If 150.0 mL of 2.50 M H2C2O4 are diluted to 580.0 mL, what is the molarity of the final solution?

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__________ M

2007-05-22 01:18:52 · 3 answers · asked by Jim H 1 in Science & Mathematics ➔ Chemistry

150.0 * 2.50 / 580.0 = 0.647 M

2007-05-22 01:29:23 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋

In dilutions,
MIVI=M2V2
M1=2.50M V1=150.0mL M2=? V2=580.0mL
M2=M1V1/V2
M2=(2.50M x150.0mL)/580.0mL=0.646M

new Molarity= 0.646M

2007-05-22 02:33:28 · answer #2 · answered by Phy A 5 · 0⤊ 0⤋

M = n / V

n = MV

M1 V1 = M2 V2 (molarity does NOT change)

2.5 * 0.15 = M2 * 0.58

M2 = 0.64655 â 0.65 M

2007-05-22 02:33:17 · answer #3 · answered by nelaq 4 · 0⤊ 0⤋