Parametric equations of a line?

Question

Does anyone know the parametric equation of the line ,
x=-t+600,y=2t-300?
Thankyou for your help

Answer 1

You've given the parametric form.
I think you want the form without the parametric variable, t:

t = 600 - x
t = (y+300)/2

so
(y+300) / 2 = 600 - x
or
y + 300 = 1200 - 2x
y + 2x = 900

Answer 2

Surely, that is the parametric equation you have written.
If you want to find dy/dx, for example, you work it out as:
(dy / dt ) / (dx / dt)
= 2 / 1
showing that the gradient is 2.
Its y intercept is where x = 0:
t + 600 = 0
t = -600
y = 2 * (-600) - 300
= -1500
Thus the y intercept is (0, -1500), and the non-parametric equation is:
y = 2x - 1500.

Answer 3

You have given the parametric equations.
t = 600 - x
y = 2.(600 - x) - 300
y = 1200 - 2x - 300
y = - 2x + 900 is equation of given line.

Answer 4

Q1. specific -- it particularly is the slope of the line tangent to the curve. Q2. specific -- it particularly is the equation of the tangent to the curve Q3. you may desire to ascertain this tangent passes via (4,3). it particularly is ensured by potential of tense that 3-[2t^3+a million]) = t(4-[3t^2+a million]) This now says that if t satisfies this equation, the line that's the tangent to the curve at (3t^2+a million,2t^3+a million) passes via (4,3). q4. See remark above. This equation is a cubic in t so could desire to have 3 roots (i'm unlikely to unravel the concern as you have asked that we dont locate the solutions.) yet we do be attentive to a minimum of one answer -- t=a million. putting t=a million in the unique definition of the curve shows that (4,3) is on the curve so the tangent to the curve at that element is going via it! desire those comments help